8x+4x-48=32-4x

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Solution for 8x+4x-48=32-4x equation: 



8x+4x-48=32-4x

We move all terms to the left:

8x+4x-48-(32-4x)=0

We add all the numbers together, and all the variables

8x+4x-(-4x+32)-48=0

We add all the numbers together, and all the variables

12x-(-4x+32)-48=0

We get rid of parentheses

12x+4x-32-48=0

We add all the numbers together, and all the variables

16x-80=0

We move all terms containing x to the left, all other terms to the right

16x=80

x=80/16

x=5

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