8x+5x-40=80-7x

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Solution for 8x+5x-40=80-7x equation: 



8x+5x-40=80-7x

We move all terms to the left:

8x+5x-40-(80-7x)=0

We add all the numbers together, and all the variables

8x+5x-(-7x+80)-40=0

We add all the numbers together, and all the variables

13x-(-7x+80)-40=0

We get rid of parentheses

13x+7x-80-40=0

We add all the numbers together, and all the variables

20x-120=0

We move all terms containing x to the left, all other terms to the right

20x=120

x=120/20

x=6

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