8x+6(40-x)=300

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Solution for 8x+6(40-x)=300 equation: 



8x+6(40-x)=300

We move all terms to the left:

8x+6(40-x)-(300)=0

We add all the numbers together, and all the variables

8x+6(-1x+40)-300=0

We multiply parentheses

8x-6x+240-300=0

We add all the numbers together, and all the variables

2x-60=0

We move all terms containing x to the left, all other terms to the right

2x=60

x=60/2

x=30

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