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8x+6=2(x+3)
We move all terms to the left:
8x+6-(2(x+3))=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
8x-2x-6+6=0
We add all the numbers together, and all the variables
6x=0
x=0/6
x=0
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