8x+6=3(8/3x+2)

Solution for 8x+6=3(8/3x+2) equation:

8x+6=3(8/3x+2)

We move all terms to the left:

8x+6-(3(8/3x+2))=0


Domain of the equation: 3x+2))!=0

x∈R


We multiply all the terms by the denominator


8x*3x+6*3x+2))-(3(8+2))=0

We add all the numbers together, and all the variables

8x*3x+6*3x+2))-(310)=0

We add all the numbers together, and all the variables

8x*3x+6*3x=0

Wy multiply elements

24x^2+18x=0

a = 24; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·24·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*24}=\frac{-36}{48}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*24}=\frac{0}{48}
=0
$