8x+6x=8x/4x+12

Solution for 8x+6x=8x/4x+12 equation:

8x+6x=8x/4x+12

We move all terms to the left:

8x+6x-(8x/4x+12)=0


Domain of the equation: 4x+12)!=0

x∈R


We add all the numbers together, and all the variables

14x-(8x/4x+12)=0

We get rid of parentheses

14x-8x/4x-12=0

We multiply all the terms by the denominator


14x*4x-8x-12*4x=0

We add all the numbers together, and all the variables

-8x+14x*4x-12*4x=0

Wy multiply elements

56x^2-8x-48x=0

We add all the numbers together, and all the variables

56x^2-56x=0

a = 56; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·56·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*56}=\frac{0}{112}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*56}=\frac{112}{112}
=1
$