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8x+7/5x+9=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
8x*5x+9*5x+7=0
Wy multiply elements
40x^2+45x+7=0
a = 40; b = 45; c = +7;
Δ = b2-4ac
Δ = 452-4·40·7
Δ = 905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{905}}{2*40}=\frac{-45-\sqrt{905}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{905}}{2*40}=\frac{-45+\sqrt{905}}{80} $
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