8x+7x=11x/3x

Solution for 8x+7x=11x/3x equation:

8x+7x=11x/3x

We move all terms to the left:

8x+7x-(11x/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

8x+7x-(+11x/3x)=0

We add all the numbers together, and all the variables

15x-(+11x/3x)=0

We get rid of parentheses

15x-11x/3x=0

We multiply all the terms by the denominator


15x*3x-11x=0

We add all the numbers together, and all the variables

-11x+15x*3x=0

Wy multiply elements

45x^2-11x=0

a = 45; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·45·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*45}=\frac{0}{90}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*45}=\frac{22}{90}
=11/45
$