8x+x(8x-8)=696

Solution for 8x+x(8x-8)=696 equation:

8x+x(8x-8)=696

We move all terms to the left:

8x+x(8x-8)-(696)=0

We multiply parentheses

8x^2+8x-8x-696=0

We add all the numbers together, and all the variables

8x^2-696=0

a = 8; b = 0; c = -696;
Δ = b2-4ac
Δ = 02-4·8·(-696)
Δ = 22272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22272}=\sqrt{256*87}=\sqrt{256}*\sqrt{87}=16\sqrt{87}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{87}}{2*8}=\frac{0-16\sqrt{87}}{16}
=-\frac{16\sqrt{87}}{16}
=-\sqrt{87}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{87}}{2*8}=\frac{0+16\sqrt{87}}{16}
=\frac{16\sqrt{87}}{16}
=\sqrt{87}
$