8x-(2-4x)=x+(3x-2)

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Solution for 8x-(2-4x)=x+(3x-2) equation: 



8x-(2-4x)=x+(3x-2)

We move all terms to the left:

8x-(2-4x)-(x+(3x-2))=0

We add all the numbers together, and all the variables

8x-(-4x+2)-(x+(3x-2))=0

We get rid of parentheses

8x+4x-(x+(3x-2))-2=0



We calculate terms in parentheses: -(x+(3x-2)), so:

x+(3x-2)

We get rid of parentheses

x+3x-2

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

12x-(4x-2)-2=0

We get rid of parentheses

12x-4x+2-2=0

We add all the numbers together, and all the variables

8x=0

x=0/8

x=0

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