8x-(2x-3((x-4)-(x+2)))=0

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Solution for 8x-(2x-3((x-4)-(x+2)))=0 equation:


Simplifying
8x + -1(2x + -3((x + -4) + -1(x + 2))) = 0

Reorder the terms:
8x + -1(2x + -3((-4 + x) + -1(x + 2))) = 0

Remove parenthesis around (-4 + x)
8x + -1(2x + -3(-4 + x + -1(x + 2))) = 0

Reorder the terms:
8x + -1(2x + -3(-4 + x + -1(2 + x))) = 0
8x + -1(2x + -3(-4 + x + (2 * -1 + x * -1))) = 0
8x + -1(2x + -3(-4 + x + (-2 + -1x))) = 0

Reorder the terms:
8x + -1(2x + -3(-4 + -2 + x + -1x)) = 0

Combine like terms: -4 + -2 = -6
8x + -1(2x + -3(-6 + x + -1x)) = 0

Combine like terms: x + -1x = 0
8x + -1(2x + -3(-6 + 0)) = 0
8x + -1(2x + -3(-6)) = 0

Multiply -3 * -6
8x + -1(2x + 18) = 0

Reorder the terms:
8x + -1(18 + 2x) = 0
8x + (18 * -1 + 2x * -1) = 0
8x + (-18 + -2x) = 0

Reorder the terms:
-18 + 8x + -2x = 0

Combine like terms: 8x + -2x = 6x
-18 + 6x = 0

Solving
-18 + 6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 6x = 0 + 18

Combine like terms: -18 + 18 = 0
0 + 6x = 0 + 18
6x = 0 + 18

Combine like terms: 0 + 18 = 18
6x = 18

Divide each side by '6'.
x = 3

Simplifying
x = 3

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