8x-(2x-3)=2(x+3,5)

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Solution for 8x-(2x-3)=2(x+3,5) equation: 



8x-(2x-3)=2(x+3.5)

We move all terms to the left:

8x-(2x-3)-(2(x+3.5))=0

We get rid of parentheses

8x-2x-(2(x+3.5))+3=0



We calculate terms in parentheses: -(2(x+3.5)), so:

2(x+3.5)

We multiply parentheses

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

6x-(2x+7)+3=0

We get rid of parentheses

6x-2x-7+3=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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