8x-(2x-9)=4x-(4+4x)=

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Solution for 8x-(2x-9)=4x-(4+4x)= equation: 



8x-(2x-9)=4x-(4+4x)=

We move all terms to the left:

8x-(2x-9)-(4x-(4+4x))=0

We add all the numbers together, and all the variables

8x-(2x-9)-(4x-(4x+4))=0

We get rid of parentheses

8x-2x-(4x-(4x+4))+9=0



We calculate terms in parentheses: -(4x-(4x+4)), so:

4x-(4x+4)

We get rid of parentheses

4x-4x-4

We add all the numbers together, and all the variables

-4

Back to the equation:

-(-4)



We add all the numbers together, and all the variables

6x+13=0

We move all terms containing x to the left, all other terms to the right

6x=-13

x=-13/6

x=-2+1/6

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