8x-(3x+7)=2(x+3)+1

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Solution for 8x-(3x+7)=2(x+3)+1 equation: 



8x-(3x+7)=2(x+3)+1

We move all terms to the left:

8x-(3x+7)-(2(x+3)+1)=0

We get rid of parentheses

8x-3x-(2(x+3)+1)-7=0



We calculate terms in parentheses: -(2(x+3)+1), so:

2(x+3)+1

We multiply parentheses

2x+6+1

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

5x-(2x+7)-7=0

We get rid of parentheses

5x-2x-7-7=0

We add all the numbers together, and all the variables

3x-14=0

We move all terms containing x to the left, all other terms to the right

3x=14

x=14/3

x=4+2/3

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