8x-(3x-5)-2x=2x(x+2)+5

Solution for 8x-(3x-5)-2x=2x(x+2)+5 equation:

8x-(3x-5)-2x=2x(x+2)+5

We move all terms to the left:

8x-(3x-5)-2x-(2x(x+2)+5)=0

We add all the numbers together, and all the variables

6x-(3x-5)-(2x(x+2)+5)=0

We get rid of parentheses

6x-3x-(2x(x+2)+5)+5=0


We calculate terms in parentheses: -(2x(x+2)+5), so:

2x(x+2)+5

We multiply parentheses

2x^2+4x+5

Back to the equation:

-(2x^2+4x+5)


We add all the numbers together, and all the variables

3x-(2x^2+4x+5)+5=0

We get rid of parentheses

-2x^2+3x-4x-5+5=0

We add all the numbers together, and all the variables

-2x^2-1x=0

a = -2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-2)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-2}=\frac{0}{-4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-2}=\frac{2}{-4}
=-1/2
$