8x-(4x+5)=3+(x+4)

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Solution for 8x-(4x+5)=3+(x+4) equation: 



8x-(4x+5)=3+(x+4)

We move all terms to the left:

8x-(4x+5)-(3+(x+4))=0

We get rid of parentheses

8x-4x-(3+(x+4))-5=0



We calculate terms in parentheses: -(3+(x+4)), so:

3+(x+4)

determiningTheFunctionDomain
(x+4)+3

We get rid of parentheses

x+4+3

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We add all the numbers together, and all the variables

4x-(x+7)-5=0

We get rid of parentheses

4x-x-7-5=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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