8x-(4x-3)+8=x+5(x+1)

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Solution for 8x-(4x-3)+8=x+5(x+1) equation: 



8x-(4x-3)+8=x+5(x+1)

We move all terms to the left:

8x-(4x-3)+8-(x+5(x+1))=0

We get rid of parentheses

8x-4x-(x+5(x+1))+3+8=0



We calculate terms in parentheses: -(x+5(x+1)), so:

x+5(x+1)

We multiply parentheses

x+5x+5

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

4x-(6x+5)+11=0

We get rid of parentheses

4x-6x-5+11=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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