8x-(5x+1)=8-2(x-3)

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Solution for 8x-(5x+1)=8-2(x-3) equation: 



8x-(5x+1)=8-2(x-3)

We move all terms to the left:

8x-(5x+1)-(8-2(x-3))=0

We get rid of parentheses

8x-5x-(8-2(x-3))-1=0



We calculate terms in parentheses: -(8-2(x-3)), so:

8-2(x-3)

determiningTheFunctionDomain
-2(x-3)+8

We multiply parentheses

-2x+6+8

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We add all the numbers together, and all the variables

3x-(-2x+14)-1=0

We get rid of parentheses

3x+2x-14-1=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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