8x-(7+3x)=2(x-5)

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Solution for 8x-(7+3x)=2(x-5) equation:



8x-(7+3x)=2(x-5)
We move all terms to the left:
8x-(7+3x)-(2(x-5))=0
We add all the numbers together, and all the variables
8x-(3x+7)-(2(x-5))=0
We get rid of parentheses
8x-3x-(2(x-5))-7=0
We calculate terms in parentheses: -(2(x-5)), so:
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
We add all the numbers together, and all the variables
5x-(2x-10)-7=0
We get rid of parentheses
5x-2x+10-7=0
We add all the numbers together, and all the variables
3x+3=0
We move all terms containing x to the left, all other terms to the right
3x=-3
x=-3/3
x=-1

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