8x-(7x+3)=2x-40

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Solution for 8x-(7x+3)=2x-40 equation:


Simplifying
8x + -1(7x + 3) = 2x + -40

Reorder the terms:
8x + -1(3 + 7x) = 2x + -40
8x + (3 * -1 + 7x * -1) = 2x + -40
8x + (-3 + -7x) = 2x + -40

Reorder the terms:
-3 + 8x + -7x = 2x + -40

Combine like terms: 8x + -7x = 1x
-3 + 1x = 2x + -40

Reorder the terms:
-3 + 1x = -40 + 2x

Solving
-3 + 1x = -40 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-3 + 1x + -2x = -40 + 2x + -2x

Combine like terms: 1x + -2x = -1x
-3 + -1x = -40 + 2x + -2x

Combine like terms: 2x + -2x = 0
-3 + -1x = -40 + 0
-3 + -1x = -40

Add '3' to each side of the equation.
-3 + 3 + -1x = -40 + 3

Combine like terms: -3 + 3 = 0
0 + -1x = -40 + 3
-1x = -40 + 3

Combine like terms: -40 + 3 = -37
-1x = -37

Divide each side by '-1'.
x = 37

Simplifying
x = 37

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