8x-(X+3)=4X-2(X-6)

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Solution for 8x-(X+3)=4X-2(X-6) equation:



8x-(x+3)=4x-2(x-6)
We move all terms to the left:
8x-(x+3)-(4x-2(x-6))=0
We get rid of parentheses
8x-x-(4x-2(x-6))-3=0
We calculate terms in parentheses: -(4x-2(x-6)), so:
4x-2(x-6)
We multiply parentheses
4x-2x+12
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
We add all the numbers together, and all the variables
7x-(2x+12)-3=0
We get rid of parentheses
7x-2x-12-3=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3

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