8x-(x+1)=2(3x-1)

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Solution for 8x-(x+1)=2(3x-1) equation:



8x-(x+1)=2(3x-1)
We move all terms to the left:
8x-(x+1)-(2(3x-1))=0
We get rid of parentheses
8x-x-(2(3x-1))-1=0
We calculate terms in parentheses: -(2(3x-1)), so:
2(3x-1)
We multiply parentheses
6x-2
Back to the equation:
-(6x-2)
We add all the numbers together, and all the variables
7x-(6x-2)-1=0
We get rid of parentheses
7x-6x+2-1=0
We add all the numbers together, and all the variables
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1

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