8x-(x+3)=3(2x+1)

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Solution for 8x-(x+3)=3(2x+1) equation: 



8x-(x+3)=3(2x+1)

We move all terms to the left:

8x-(x+3)-(3(2x+1))=0

We get rid of parentheses

8x-x-(3(2x+1))-3=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

7x-(6x+3)-3=0

We get rid of parentheses

7x-6x-3-3=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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