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8x-10/13x-2x=1
We move all terms to the left:
8x-10/13x-2x-(1)=0
Domain of the equation: 13x!=0We add all the numbers together, and all the variables
x!=0/13
x!=0
x∈R
6x-10/13x-1=0
We multiply all the terms by the denominator
6x*13x-1*13x-10=0
Wy multiply elements
78x^2-13x-10=0
a = 78; b = -13; c = -10;
Δ = b2-4ac
Δ = -132-4·78·(-10)
Δ = 3289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{3289}}{2*78}=\frac{13-\sqrt{3289}}{156} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{3289}}{2*78}=\frac{13+\sqrt{3289}}{156} $
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