8x-10=2x(3x+4)

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Solution for 8x-10=2x(3x+4) equation: 



8x-10=2x(3x+4)

We move all terms to the left:

8x-10-(2x(3x+4))=0



We calculate terms in parentheses: -(2x(3x+4)), so:

2x(3x+4)

We multiply parentheses

6x^2+8x

Back to the equation:

-(6x^2+8x)



We get rid of parentheses

-6x^2+8x-8x-10=0

We add all the numbers together, and all the variables

-6x^2-10=0

a = -6; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-6)·(-10)
Δ = -240
Delta is less than zero, so there is no solution for the equation

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