8x-10=3(2x+20)

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Solution for 8x-10=3(2x+20) equation:



8x-10=3(2x+20)
We move all terms to the left:
8x-10-(3(2x+20))=0
We calculate terms in parentheses: -(3(2x+20)), so:
3(2x+20)
We multiply parentheses
6x+60
Back to the equation:
-(6x+60)
We get rid of parentheses
8x-6x-60-10=0
We add all the numbers together, and all the variables
2x-70=0
We move all terms containing x to the left, all other terms to the right
2x=70
x=70/2
x=35

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