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8x-12=2x+3(2x-4)
We move all terms to the left:
8x-12-(2x+3(2x-4))=0
We calculate terms in parentheses: -(2x+3(2x-4)), so:We get rid of parentheses
2x+3(2x-4)
We multiply parentheses
2x+6x-12
We add all the numbers together, and all the variables
8x-12
Back to the equation:
-(8x-12)
8x-8x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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