8x-16=8x(x-2)

Solution for 8x-16=8x(x-2) equation:

8x-16=8x(x-2)

We move all terms to the left:

8x-16-(8x(x-2))=0


We calculate terms in parentheses: -(8x(x-2)), so:

8x(x-2)

We multiply parentheses

8x^2-16x

Back to the equation:

-(8x^2-16x)


We get rid of parentheses

-8x^2+8x+16x-16=0

We add all the numbers together, and all the variables

-8x^2+24x-16=0

a = -8; b = 24; c = -16;
Δ = b2-4ac
Δ = 242-4·(-8)·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8}{2*-8}=\frac{-32}{-16}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8}{2*-8}=\frac{-16}{-16}
=1
$