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8x-1=1+5(6+8x)
We move all terms to the left:
8x-1-(1+5(6+8x))=0
We add all the numbers together, and all the variables
8x-(1+5(8x+6))-1=0
We calculate terms in parentheses: -(1+5(8x+6)), so:We get rid of parentheses
1+5(8x+6)
determiningTheFunctionDomain 5(8x+6)+1
We multiply parentheses
40x+30+1
We add all the numbers together, and all the variables
40x+31
Back to the equation:
-(40x+31)
8x-40x-31-1=0
We add all the numbers together, and all the variables
-32x-32=0
We move all terms containing x to the left, all other terms to the right
-32x=32
x=32/-32
x=-1
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