8x-2(1-3x)=5+7(-1+2x)

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Solution for 8x-2(1-3x)=5+7(-1+2x) equation: 



8x-2(1-3x)=5+7(-1+2x)

We move all terms to the left:

8x-2(1-3x)-(5+7(-1+2x))=0

We add all the numbers together, and all the variables

8x-2(-3x+1)-(5+7(2x-1))=0

We multiply parentheses

8x+6x-(5+7(2x-1))-2=0



We calculate terms in parentheses: -(5+7(2x-1)), so:

5+7(2x-1)

determiningTheFunctionDomain
7(2x-1)+5

We multiply parentheses

14x-7+5

We add all the numbers together, and all the variables

14x-2

Back to the equation:

-(14x-2)



We add all the numbers together, and all the variables

14x-(14x-2)-2=0

We get rid of parentheses

14x-14x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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