8x-2(2+3x)=2(1-2x)-3(x-1)

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Solution for 8x-2(2+3x)=2(1-2x)-3(x-1) equation: 



8x-2(2+3x)=2(1-2x)-3(x-1)

We move all terms to the left:

8x-2(2+3x)-(2(1-2x)-3(x-1))=0

We add all the numbers together, and all the variables

8x-2(3x+2)-(2(-2x+1)-3(x-1))=0

We multiply parentheses

8x-6x-(2(-2x+1)-3(x-1))-4=0



We calculate terms in parentheses: -(2(-2x+1)-3(x-1)), so:

2(-2x+1)-3(x-1)

We multiply parentheses

-4x-3x+2+3

We add all the numbers together, and all the variables

-7x+5

Back to the equation:

-(-7x+5)



We add all the numbers together, and all the variables

2x-(-7x+5)-4=0

We get rid of parentheses

2x+7x-5-4=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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