8x-2(2-3x)=4(x-4)-38

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Solution for 8x-2(2-3x)=4(x-4)-38 equation: 



8x-2(2-3x)=4(x-4)-38

We move all terms to the left:

8x-2(2-3x)-(4(x-4)-38)=0

We add all the numbers together, and all the variables

8x-2(-3x+2)-(4(x-4)-38)=0

We multiply parentheses

8x+6x-(4(x-4)-38)-4=0



We calculate terms in parentheses: -(4(x-4)-38), so:

4(x-4)-38

We multiply parentheses

4x-16-38

We add all the numbers together, and all the variables

4x-54

Back to the equation:

-(4x-54)



We add all the numbers together, and all the variables

14x-(4x-54)-4=0

We get rid of parentheses

14x-4x+54-4=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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