8x-2(3-2x)=4(x-5)-10

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Solution for 8x-2(3-2x)=4(x-5)-10 equation: 



8x-2(3-2x)=4(x-5)-10

We move all terms to the left:

8x-2(3-2x)-(4(x-5)-10)=0

We add all the numbers together, and all the variables

8x-2(-2x+3)-(4(x-5)-10)=0

We multiply parentheses

8x+4x-(4(x-5)-10)-6=0



We calculate terms in parentheses: -(4(x-5)-10), so:

4(x-5)-10

We multiply parentheses

4x-20-10

We add all the numbers together, and all the variables

4x-30

Back to the equation:

-(4x-30)



We add all the numbers together, and all the variables

12x-(4x-30)-6=0

We get rid of parentheses

12x-4x+30-6=0

We add all the numbers together, and all the variables

8x+24=0

We move all terms containing x to the left, all other terms to the right

8x=-24

x=-24/8

x=-3

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