8x-2(3-2x)=5(x-5)-5

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Solution for 8x-2(3-2x)=5(x-5)-5 equation: 



8x-2(3-2x)=5(x-5)-5

We move all terms to the left:

8x-2(3-2x)-(5(x-5)-5)=0

We add all the numbers together, and all the variables

8x-2(-2x+3)-(5(x-5)-5)=0

We multiply parentheses

8x+4x-(5(x-5)-5)-6=0



We calculate terms in parentheses: -(5(x-5)-5), so:

5(x-5)-5

We multiply parentheses

5x-25-5

We add all the numbers together, and all the variables

5x-30

Back to the equation:

-(5x-30)



We add all the numbers together, and all the variables

12x-(5x-30)-6=0

We get rid of parentheses

12x-5x+30-6=0

We add all the numbers together, and all the variables

7x+24=0

We move all terms containing x to the left, all other terms to the right

7x=-24

x=-24/7

x=-3+3/7

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