8x-2(3x+1)=(-2x-10)

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Solution for 8x-2(3x+1)=(-2x-10) equation: 



8x-2(3x+1)=(-2x-10)

We move all terms to the left:

8x-2(3x+1)-((-2x-10))=0

We multiply parentheses

8x-6x-((-2x-10))-2=0



We calculate terms in parentheses: -((-2x-10)), so:

(-2x-10)

We get rid of parentheses

-2x-10

Back to the equation:

-(-2x-10)



We add all the numbers together, and all the variables

2x-(-2x-10)-2=0

We get rid of parentheses

2x+2x+10-2=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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