8x-2(4-3x)=5(x-4)-42

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Solution for 8x-2(4-3x)=5(x-4)-42 equation: 



8x-2(4-3x)=5(x-4)-42

We move all terms to the left:

8x-2(4-3x)-(5(x-4)-42)=0

We add all the numbers together, and all the variables

8x-2(-3x+4)-(5(x-4)-42)=0

We multiply parentheses

8x+6x-(5(x-4)-42)-8=0



We calculate terms in parentheses: -(5(x-4)-42), so:

5(x-4)-42

We multiply parentheses

5x-20-42

We add all the numbers together, and all the variables

5x-62

Back to the equation:

-(5x-62)



We add all the numbers together, and all the variables

14x-(5x-62)-8=0

We get rid of parentheses

14x-5x+62-8=0

We add all the numbers together, and all the variables

9x+54=0

We move all terms containing x to the left, all other terms to the right

9x=-54

x=-54/9

x=-6

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