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8x-2(x+1)=2(3x-)
We move all terms to the left:
8x-2(x+1)-(2(3x-))=0
We add all the numbers together, and all the variables
8x-2(x+1)-(2(+3x))=0
We multiply parentheses
8x-2x-(2(+3x))-2=0
We calculate terms in parentheses: -(2(+3x)), so:We add all the numbers together, and all the variables
2(+3x)
We multiply parentheses
6x
Back to the equation:
-(6x)
-2!=0
There is no solution for this equation
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