8x-2(x+1)=4-(2x+3)

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Solution for 8x-2(x+1)=4-(2x+3) equation: 



8x-2(x+1)=4-(2x+3)

We move all terms to the left:

8x-2(x+1)-(4-(2x+3))=0

We multiply parentheses

8x-2x-(4-(2x+3))-2=0



We calculate terms in parentheses: -(4-(2x+3)), so:

4-(2x+3)

determiningTheFunctionDomain
-(2x+3)+4

We get rid of parentheses

-2x-3+4

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

6x-(-2x+1)-2=0

We get rid of parentheses

6x+2x-1-2=0

We add all the numbers together, and all the variables

8x-3=0

We move all terms containing x to the left, all other terms to the right

8x=3

x=3/8

x=3/8

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