8x-2(x+3)=4(x+4)

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Solution for 8x-2(x+3)=4(x+4) equation: 



8x-2(x+3)=4(x+4)

We move all terms to the left:

8x-2(x+3)-(4(x+4))=0

We multiply parentheses

8x-2x-(4(x+4))-6=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

6x-(4x+16)-6=0

We get rid of parentheses

6x-4x-16-6=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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