8x-2(x-5)=(x-1)

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Solution for 8x-2(x-5)=(x-1) equation: 



8x-2(x-5)=(x-1)

We move all terms to the left:

8x-2(x-5)-((x-1))=0

We multiply parentheses

8x-2x-((x-1))+10=0



We calculate terms in parentheses: -((x-1)), so:

(x-1)

We get rid of parentheses

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

6x-(x-1)+10=0

We get rid of parentheses

6x-x+1+10=0

We add all the numbers together, and all the variables

5x+11=0

We move all terms containing x to the left, all other terms to the right

5x=-11

x=-11/5

x=-2+1/5

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