8x-2(x-5)=6(x+1)+2

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Solution for 8x-2(x-5)=6(x+1)+2 equation:


Simplifying
8x + -2(x + -5) = 6(x + 1) + 2

Reorder the terms:
8x + -2(-5 + x) = 6(x + 1) + 2
8x + (-5 * -2 + x * -2) = 6(x + 1) + 2
8x + (10 + -2x) = 6(x + 1) + 2

Reorder the terms:
10 + 8x + -2x = 6(x + 1) + 2

Combine like terms: 8x + -2x = 6x
10 + 6x = 6(x + 1) + 2

Reorder the terms:
10 + 6x = 6(1 + x) + 2
10 + 6x = (1 * 6 + x * 6) + 2
10 + 6x = (6 + 6x) + 2

Reorder the terms:
10 + 6x = 6 + 2 + 6x

Combine like terms: 6 + 2 = 8
10 + 6x = 8 + 6x

Add '-6x' to each side of the equation.
10 + 6x + -6x = 8 + 6x + -6x

Combine like terms: 6x + -6x = 0
10 + 0 = 8 + 6x + -6x
10 = 8 + 6x + -6x

Combine like terms: 6x + -6x = 0
10 = 8 + 0
10 = 8

Solving
10 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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