8x-2+2(3x+4)=(4x+1)

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Solution for 8x-2+2(3x+4)=(4x+1) equation: 



8x-2+2(3x+4)=(4x+1)

We move all terms to the left:

8x-2+2(3x+4)-((4x+1))=0

We multiply parentheses

8x+6x-((4x+1))+8-2=0



We calculate terms in parentheses: -((4x+1)), so:

(4x+1)

We get rid of parentheses

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

14x-(4x+1)+6=0

We get rid of parentheses

14x-4x-1+6=0

We add all the numbers together, and all the variables

10x+5=0

We move all terms containing x to the left, all other terms to the right

10x=-5

x=-5/10

x=-1/2

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