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8x-20(x+1)=-(9x+10)+2(2x-5
We move all terms to the left:
8x-20(x+1)-(-(9x+10)+2(2x-5)=0
We multiply parentheses
8x-20x-(-(9x+10)+2(2x-5)-20=0
We add all the numbers together, and all the variables
-12x-(-(9x+10)+2(2x-5)-20=0
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