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8x-20(x+1)=-(9x+10)+2(2x-5)
We move all terms to the left:
8x-20(x+1)-(-(9x+10)+2(2x-5))=0
We multiply parentheses
8x-20x-(-(9x+10)+2(2x-5))-20=0
We calculate terms in parentheses: -(-(9x+10)+2(2x-5)), so:We add all the numbers together, and all the variables
-(9x+10)+2(2x-5)
We multiply parentheses
-(9x+10)+4x-10
We get rid of parentheses
-9x+4x-10-10
We add all the numbers together, and all the variables
-5x-20
Back to the equation:
-(-5x-20)
-12x-(-5x-20)-20=0
We get rid of parentheses
-12x+5x+20-20=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
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