8x-20-2x=6(x+2)-32

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Solution for 8x-20-2x=6(x+2)-32 equation: 



8x-20-2x=6(x+2)-32

We move all terms to the left:

8x-20-2x-(6(x+2)-32)=0

We add all the numbers together, and all the variables

6x-(6(x+2)-32)-20=0



We calculate terms in parentheses: -(6(x+2)-32), so:

6(x+2)-32

We multiply parentheses

6x+12-32

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

6x-6x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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