8x-27+5(2x-3)=62-(3x+8)

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Solution for 8x-27+5(2x-3)=62-(3x+8) equation: 



8x-27+5(2x-3)=62-(3x+8)

We move all terms to the left:

8x-27+5(2x-3)-(62-(3x+8))=0

We multiply parentheses

8x+10x-(62-(3x+8))-15-27=0



We calculate terms in parentheses: -(62-(3x+8)), so:

62-(3x+8)

determiningTheFunctionDomain
-(3x+8)+62

We get rid of parentheses

-3x-8+62

We add all the numbers together, and all the variables

-3x+54

Back to the equation:

-(-3x+54)



We add all the numbers together, and all the variables

18x-(-3x+54)-42=0

We get rid of parentheses

18x+3x-54-42=0

We add all the numbers together, and all the variables

21x-96=0

We move all terms containing x to the left, all other terms to the right

21x=96

x=96/21

x=4+4/7

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