8x-3(2x-4)=3(x-6)=

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Solution for 8x-3(2x-4)=3(x-6)= equation: 



8x-3(2x-4)=3(x-6)=

We move all terms to the left:

8x-3(2x-4)-(3(x-6))=0

We multiply parentheses

8x-6x-(3(x-6))+12=0



We calculate terms in parentheses: -(3(x-6)), so:

3(x-6)

We multiply parentheses

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

2x-(3x-18)+12=0

We get rid of parentheses

2x-3x+18+12=0

We add all the numbers together, and all the variables

-1x+30=0

We move all terms containing x to the left, all other terms to the right

-x=-30

x=-30/-1

x=+30

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