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8x-3(2x-4)=4(6x+4)-4
We move all terms to the left:
8x-3(2x-4)-(4(6x+4)-4)=0
We multiply parentheses
8x-6x-(4(6x+4)-4)+12=0
We calculate terms in parentheses: -(4(6x+4)-4), so:We add all the numbers together, and all the variables
4(6x+4)-4
We multiply parentheses
24x+16-4
We add all the numbers together, and all the variables
24x+12
Back to the equation:
-(24x+12)
2x-(24x+12)+12=0
We get rid of parentheses
2x-24x-12+12=0
We add all the numbers together, and all the variables
-22x=0
x=0/-22
x=0
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