8x-3(2x-5)=39+4x-6x

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Solution for 8x-3(2x-5)=39+4x-6x equation: 



8x-3(2x-5)=39+4x-6x

We move all terms to the left:

8x-3(2x-5)-(39+4x-6x)=0

We add all the numbers together, and all the variables

8x-3(2x-5)-(-2x+39)=0

We multiply parentheses

8x-6x-(-2x+39)+15=0

We get rid of parentheses

8x-6x+2x-39+15=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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