8x-3(4-2x)=6(y+1)-2

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Solution for 8x-3(4-2x)=6(y+1)-2 equation:


Simplifying
8x + -3(4 + -2x) = 6(y + 1) + -2
8x + (4 * -3 + -2x * -3) = 6(y + 1) + -2
8x + (-12 + 6x) = 6(y + 1) + -2

Reorder the terms:
-12 + 8x + 6x = 6(y + 1) + -2

Combine like terms: 8x + 6x = 14x
-12 + 14x = 6(y + 1) + -2

Reorder the terms:
-12 + 14x = 6(1 + y) + -2
-12 + 14x = (1 * 6 + y * 6) + -2
-12 + 14x = (6 + 6y) + -2

Reorder the terms:
-12 + 14x = 6 + -2 + 6y

Combine like terms: 6 + -2 = 4
-12 + 14x = 4 + 6y

Solving
-12 + 14x = 4 + 6y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 14x = 4 + 12 + 6y

Combine like terms: -12 + 12 = 0
0 + 14x = 4 + 12 + 6y
14x = 4 + 12 + 6y

Combine like terms: 4 + 12 = 16
14x = 16 + 6y

Divide each side by '14'.
x = 1.142857143 + 0.4285714286y

Simplifying
x = 1.142857143 + 0.4285714286y

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